java – “包应包含内容类型部分[M1.13]”
发布时间:2020-09-21 08:19:57 所属栏目:Java 来源:互联网
导读:我试图写入Excel文件,但我一直收到错误: Exception in thread “main” org.apache.poi.POIXMLException: org.apache.poi.openxml4j.exceptions.InvalidFormatException: Package should contain a content type part [M1.13] 根据我的理解,
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我试图写入Excel文件,但我一直收到错误:
根据我的理解,我错过了一个jar文件. 任何人都可以帮我识别它是哪个文件? 附:我正在使用Netbeans. import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import javax.swing.JOptionPane;
import org.apache.poi.openxml4j.exceptions.InvalidFormatException;
import org.apache.poi.xssf.usermodel.XSSFCell;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;
/**
*
* @author nicholaskissaun
*/
public class Tester {
public static void main (String args [])throws FileNotFoundException,IOException,InvalidFormatException{
int RowCount = 7,iChoice;
String sChoice;
XSSFSheet s;
XSSFRow row1;
XSSFWorkbook wb;
XSSFCell r1c1,r1c2,r1c8,r1Episodes;
FileInputStream fis = new FileInputStream("/Users/nicholaskissaun/Google Drive/Grade 11_12/Computer Science/Java/Term1/src/IA/Profiles/Becky/ShowDetails.xlsx");
wb = new XSSFWorkbook(fis);
s = wb.getSheetAt(0);
}
}
解决方法使用文件扩展名来处理WorkSheet类型String inputFilename = new File(path).getName();
switch (inputFilename.substring(inputFilename.lastIndexOf(".") + 1,inputFilename.length())) {
case "xls":
return readXLS(path);
case "xlsx":
return readXLSX(path);
default:
Log.e(TAG,"No XLS file chosen");
return "Please select valid "Excel" File"";
}
对于XLSX文件:使用XSSFWorkbook& XSSFSheet XSSFWorkbook workbook = new XSSFWorkbook(new FileInputStream(new File(path)));
XSSFSheet sheet = workbook.getSheetAt(0);
对于XLS文件:使用HSSFWorkbook& HSSFSheet HSSFWorkbook workbook = new HSSFWorkbook(new FileInputStream(new File(path)));
HSSFSheet sheet = workbook.getSheetAt(0); (编辑:鄂州站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
